Segher Boessenkool wrote:

quoted

quoted

Surely there is something called something like of_node_is_compatible()
you can use here?  You already have the node pointer, there is no need
to look at all other nodes.

I see the point.
I didn't find of_node_is_compatible() but I'll look what's available
here.

int of_device_is_compatible(const struct device_node *device,
                const char *compat)

Thanks. I'll pick that.

Cheers,
Albert