On 08/30/2018 08:49 AM, Jann Horn wrote:
quoted
@@ -1203,7 +1203,28 @@ static inline pte_t ptep_get_and_clear_full(struct mm_struct *mm,
static inline void ptep_set_wrprotect(struct mm_struct *mm,
unsigned long addr, pte_t *ptep)
{
+ pte_t pte;
+
clear_bit(_PAGE_BIT_RW, (unsigned long *)&ptep->pte);
+ pte = *ptep;
+
+ /*
+ * Some processors can start a write, but ending up seeing
+ * a read-only PTE by the time they get to the Dirty bit.
+ * In this case, they will set the Dirty bit, leaving a
+ * read-only, Dirty PTE which looks like a Shadow Stack PTE.
+ *
+ * However, this behavior has been improved and will not occur
+ * on processors supporting Shadow Stacks. Without this
+ * guarantee, a transition to a non-present PTE and flush the
+ * TLB would be needed.
+ *
+ * When change a writable PTE to read-only and if the PTE has
+ * _PAGE_DIRTY_HW set, we move that bit to _PAGE_DIRTY_SW so
+ * that the PTE is not a valid Shadow Stack PTE.
+ */
+ pte = pte_move_flags(pte, _PAGE_DIRTY_HW, _PAGE_DIRTY_SW);
+ set_pte_at(mm, addr, ptep, pte);
}
I don't understand why it's okay that you first atomically clear the
RW bit, then atomically switch from DIRTY_HW to DIRTY_SW. Doesn't that
mean that between the two atomic writes, another core can incorrectly
see a shadow stack?
Good point.
This could result in a spurious shadow-stack fault, or allow a
shadow-stack write to the page in the transient state.
But, the shadow-stack permissions are more restrictive than what could
be in the TLB at this point, so I don't think there's a real security
implication here.
The only trouble is handling the spurious shadow-stack fault. The
alternative is to go !Present for a bit, which we would probably just
handle fine in the existing page fault code.