Re: kprobe: __blkdev_put probe is missed
From: Ming Lei <hidden>
Date: 2020-06-22 00:28:12
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Hi Masami, On Sat, Jun 20, 2020 at 10:37:47AM +0900, Masami Hiramatsu wrote:
Hi Ming, On Sat, 20 Jun 2020 07:28:20 +0800 Ming Lei [off-list ref] wrote:quoted
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Ah, after all it is as expected. With your kconfig, the kernel is very agressively optimized. $ objdump -dS vmlinux | less ... ffffffff81256dc3 <__blkdev_put>: { ffffffff81256dc3: e8 98 85 df ff callq ffffffff8104f360 <__fentry__> ffffffff81256dc8: 41 57 push %r15 ffffffff81256dca: 41 56 push %r14 ffffffff81256dcc: 41 55 push %r13 ... ffffffff81256f05: 75 02 jne ffffffff81256f09 <__blkdev_put+0x146> struct block_device *victim = NULL; ffffffff81256f07: 31 db xor %ebx,%ebx bdev->bd_contains = NULL; ffffffff81256f09: 48 c7 45 60 00 00 00 movq $0x0,0x60(%rbp) ffffffff81256f10: 00 put_disk_and_module(disk); ffffffff81256f11: 4c 89 f7 mov %r14,%rdi ffffffff81256f14: e8 c6 3d 11 00 callq ffffffff8136acdf <put_disk_and_module> mutex_unlock(&bdev->bd_mutex); ffffffff81256f19: 4c 89 ff mov %r15,%rdi __blkdev_put(victim, mode, 1); ffffffff81256f1c: 41 bc 01 00 00 00 mov $0x1,%r12d mutex_unlock(&bdev->bd_mutex); ffffffff81256f22: e8 8d d7 48 00 callq ffffffff816e46b4 <mutex_unlock> bdput(bdev); ffffffff81256f27: 48 89 ef mov %rbp,%rdi ffffffff81256f2a: e8 f0 e9 ff ff callq ffffffff8125591f <bdput> if (victim) ffffffff81256f2f: 48 85 db test %rbx,%rbx ffffffff81256f32: 74 08 je ffffffff81256f3c <__blkdev_put+0x179> ffffffff81256f34: 48 89 dd mov %rbx,%rbp ffffffff81256f37: e9 b4 fe ff ff jmpq ffffffff81256df0 <__blkdev_put+0x2d> <<-----THIS!! } ffffffff81256f3c: 48 8b 44 24 28 mov 0x28(%rsp),%rax ffffffff81256f41: 65 48 33 04 25 28 00 xor %gs:0x28,%rax ffffffff81256f48: 00 00 ffffffff81256f4a: 74 05 je ffffffff81256f51 <__blkdev_put+0x18e> ffffffff81256f4c: e8 5a 4e 48 00 callq ffffffff816dbdab <__stack_chk_fail> ffffffff81256f51: 48 83 c4 30 add $0x30,%rsp ffffffff81256f55: 5b pop %rbx ffffffff81256f56: 5d pop %rbp ffffffff81256f57: 41 5c pop %r12 ffffffff81256f59: 41 5d pop %r13 ffffffff81256f5b: 41 5e pop %r14 ffffffff81256f5d: 41 5f pop %r15 ffffffff81256f5f: c3 retq As you can see, the nested __blkdev_put() is coverted to a loop. If you put kprobe on __blkdev_put+0x2d, you'll see the event twice.Thanks for your investigation. Some trace tools can just trace on function entry, such as bcc, and some user script always trace on function entry. I guess the issue should belong to kprobe implementation: 1) __blkdev_put() is capable of being kprobed, so from user view, the probe on entry of __blkdev_put() should be triggeredYes, it is correctly triggered.
I mean it isn't from user's viewpoint, and the binary code is usually a black box for final kprobe user. IMO, all your and Steven's input are just from kprobe/trace developer's viewpoint. Can you think about the issue from kprobe real/final user? Trace is very useful tools to observe system internal, and people often relies on trace to understand system. However, missed probe often causes trouble for us to understand the system correctly.
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2) from implementation view, I understand exception should be trapped on the entry of __blkdev_put(), looks it isn't done.No, it is correctly trapped the function entry address. The problem is that the gcc optimized the nested function call into jump to the beginning of function body (skip prologue). Usually, a function is compiled as below func() (1) the entry address (func:) { (2) the function prologue (setup stackframe) int a (3) the beginning of function body ... func() (4) the nested function call And in this case, the gcc optimized (4) into jump to (3) instead of actual function call instruction. Thus, for the nested case (1) and (2) are skipped. IOW, the code flow becomes (1)->(2)->(3)->(4)->(3) instead of (1)->(2)->(3)->(4)->(1)->(2)->(3) In this case, if we put a probe on (1) or (2), those are disappeared in the nested call. Thus if you put a probe on (3) ('perf probe __blkdev_put:2') you'll see the event twice.
Thanks for your explanation. Can you kprobe guys improve the implementation for covering this case? For example, put probe on 3) in case the above situation is recognized. Thanks, Ming