Thread (117 messages) 117 messages, 14 authors, 2020-03-07

Re: [PATCH 00/17] VFS: Filesystem information and notifications [ver #17]

From: Jens Axboe <axboe@kernel.dk>
Date: 2020-03-03 20:33:08
Also in: linux-fsdevel, lkml

On 3/3/20 12:43 PM, Jeff Layton wrote:
On Tue, 2020-03-03 at 12:23 -0700, Jens Axboe wrote:
quoted
On 3/3/20 12:02 PM, Jeff Layton wrote:
quoted
Basically, all you'd need to do is keep a pointer to struct file in the
internal state for the chain. Then, allow userland to specify some magic
fd value for subsequent chained operations that says to use that instead
of consulting the fdtable. Maybe use -4096 (-MAX_ERRNO - 1)?
BTW, I think we need two magics here. One that says "result from
previous is fd for next", and one that says "fd from previous is fd for
next". The former allows inheritance from open -> read, the latter from
read -> write.
Do we? I suspect that in almost all of the cases, all we'd care about is
the last open. Also if you have unrelated operations in there you still
have to chain the fd through somehow to the next op which is a bit hard
to do with that scheme.

I'd just have a single magic carveout that means "use the result of last
open call done in this chain". If you do a second open (or pipe, or...),
then that would put the old struct file pointer and drop a new one in
there.

If we really do want to enable multiple opens in a single chain though,
then we might want to rethink this and consider some sort of slot table
for storing open fds.
I think the one magic can work, you just have to define your chain
appropriately for the case where you have multiple opens. That's true
for the two magic approach as well, of course, I don't want a stack of
open fds, just "last open" should suffice.

I don't like the implicit close, if your op opens an fd, something
should close it again. You pass it back to the application in any case
for io_uring, so the app can just close it. Which means that your chain
should just include a close for whatever fd you open, unless you plan on
using it in the application aftwards.

-- 
Jens Axboe
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