Thread (91 messages) flat view 91 messages, 7 authors, 2017-04-14

Re: [PATCH v3 02/10] eal: probe new virtual bus after other bus devices

From: Jan Blunck <hidden>
Date: 2017-02-27 09:09:06

On Mon, Feb 27, 2017 at 9:59 AM, Shreyansh Jain [off-list ref] wrote:
On Saturday 25 February 2017 03:58 PM, Jan Blunck wrote:
quoted
Also see commit f4ce209a ("eal: postpone vdev initialization").

Signed-off-by: Jan Blunck <redacted>
---
 lib/librte_eal/common/eal_common_bus.c | 16 +++++++++++++++-
 1 file changed, 15 insertions(+), 1 deletion(-)
diff --git a/lib/librte_eal/common/eal_common_bus.c
b/lib/librte_eal/common/eal_common_bus.c
index 4638e78..8f9baf8 100644
--- a/lib/librte_eal/common/eal_common_bus.c
+++ b/lib/librte_eal/common/eal_common_bus.c
@@ -86,9 +86,14 @@ int
 rte_bus_probe(void)
 {
        int ret;
-       struct rte_bus *bus;
+       struct rte_bus *bus, *vbus = NULL;

        TAILQ_FOREACH(bus, &rte_bus_list, next) {
+               if (!strcmp(bus->name, "virtual")) {
+                       vbus = bus;
+                       continue;
+               }
+
                ret = bus->probe();
                if (ret) {
                        RTE_LOG(ERR, EAL, "Bus (%s) probe failed.\n",
@@ -97,6 +102,15 @@ rte_bus_probe(void)
                }
        }

+       if (vbus) {
+               ret = vbus->probe();
+               if (ret) {
+                       RTE_LOG(ERR, EAL, "Bus (%s) probe failed.\n",
+                               vbus->name);
+                       return ret;
+               }
+       }
+

This has probably changed to do away with priority of RTE_REGISTER_*
macro.

This is based on an assumption that there is only a single 'virtual'
bus and no driver ever registers another bus with the same name.

The problem originates from the fact that rte_bus_register is
_not_ checking for duplicate entries while registering.
(Apparently, it would be a problem in case of RTE_* macros as well).

I think that should be fixed.

If we are in sync, I will push a patch.
Indeed. The buses should have a unique name.
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