[ 158/171] libceph: avoid dropping con mutex before fault
From: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
Date: 2012-11-22 21:28:14
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3.4-stable review patch. If anyone has any objections, please let me know. ------------------ From: Sage Weil <redacted> (cherry picked from commit 8636ea672f0c5ab7478c42c5b6705ebd1db7eb6a) The ceph_fault() function takes the con mutex, so we should avoid dropping it before calling it. This fixes a potential race with another thread calling ceph_con_close(), or _open(), or similar (we don't reverify con->state after retaking the lock). Add annotation so that lockdep realizes we will drop the mutex before returning. Signed-off-by: Sage Weil <redacted> Reviewed-by: Alex Elder <redacted> Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org> --- net/ceph/messenger.c | 4 +--- 1 file changed, 1 insertion(+), 3 deletions(-)
--- a/net/ceph/messenger.c
+++ b/net/ceph/messenger.c@@ -2336,7 +2336,6 @@ done_unlocked: return; fault: - mutex_unlock(&con->mutex); ceph_fault(con); /* error/fault path */ goto done_unlocked; }
@@ -2347,9 +2346,8 @@ fault: * exponential backoff */ static void ceph_fault(struct ceph_connection *con) + __releases(con->mutex) { - mutex_lock(&con->mutex); - pr_err("%s%lld %s %s\n", ENTITY_NAME(con->peer_name), ceph_pr_addr(&con->peer_addr.in_addr), con->error_msg); dout("fault %p state %lu to peer %s\n",