Thread (4 messages) flat view 4 messages, 4 authors, 2021-05-13

Re: [PATCH] net: mdio: octeon: Fix some double free issues

From: Russell King - ARM Linux admin <linux@armlinux.org.uk>
Date: 2021-05-13 09:44:38
Also in: kernel-janitors, lkml

On Thu, May 13, 2021 at 09:24:55AM +0200, Christophe JAILLET wrote:
'bus->mii_bus' has been allocated with 'devm_mdiobus_alloc_size()' in the
probe function. So it must not be freed explicitly or there will be a
double free.

Remove the incorrect 'mdiobus_free' in the error handling path of the
probe function and in remove function.

Suggested-By: Andrew Lunn <andrew@lunn.ch>
Fixes: 35d2aeac9810 ("phy: mdio-octeon: Use devm_mdiobus_alloc_size()")
Signed-off-by: Christophe JAILLET <redacted>
Reviewed-by: Russell King <redacted>
---
The 'smi_en.u64 = 0; oct_mdio_writeq()' looks odd to me. Usually the normal
path and the error handling path don't write the same value. Here, both
write 0.
Having '1' somewhere would 'look' more usual. :)
More over I think that 'smi_en.s.en = 1;' in the probe is useless.
It looks fine to me.

        smi_en.u64 = 0;
        smi_en.s.en = 1;
        oct_mdio_writeq(smi_en.u64, bus->register_base + SMI_EN);

smi_en is a union of a u64 and a structure containing a bitfield. s.en
corresponds on LE systems with the u64 bit 0. So the above has the
effect of writing a u64 value of '1' to the SMI_EN register, whereas:

        smi_en.u64 = 0;
        oct_mdio_writeq(smi_en.u64, bus->register_base + SMI_EN);

has the effect of writing a u64 value of '0' to the SMI_EN register.

This code is fine.

-- 
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