Thread (25 messages) 25 messages, 8 authors, 2011-09-19

Re: [PATCH -next v2] unix stream: Fix use-after-free crashes

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From: Yan, Zheng <hidden>
Date: 2011-09-06 23:09:18

On Wed, Sep 7, 2011 at 4:19 AM, Eric Dumazet [off-list ref] wrote:
Le mardi 06 septembre 2011 à 12:59 -0700, Tim Chen a écrit :
quoted
On Tue, 2011-09-06 at 21:43 +0200, Eric Dumazet wrote:
quoted
Le mardi 06 septembre 2011 à 12:33 -0700, Tim Chen a écrit :
quoted
Yes, I think locking the sendmsg for the entire duration of
unix_stream_sendmsg makes a lot of sense.  It simplifies the logic a lot
more.  I'll try to cook something up in the next couple of days.
Thats not really possible, we cant hold a spinlock and call
sock_alloc_send_skb() and/or memcpy_fromiovec(), wich might sleep.

You would need to prepare the full skb list, then :
- stick the ref on the last skb of the list.

Transfert the whole skb list in other->sk_receive_queue in one go,
instead of one after another.

Unfortunately, this would break streaming (big send(), and another
thread doing the receive)

Listen, I am wondering why hackbench even triggers SCM code. This is
really odd. We should not have a _single_ pid/cred ref/unref at all.
Hackbench triggers the code because it has a bunch of threads sending
msgs on UNIX socket.
quoted
Well, if the lock socket approach doesn't work, then my original patch
plus Yan Zheng's fix should still work.  I'll try to answer your
objections below:

quoted
I was discussing of things after proposed patch, not current net-next.

This reads :

err = unix_scm_to_skb(siocb->scm, skb, !fds_sent, scm_ref);

So first skb is sent without ref taken, as mentioned in Changelog ?
No. the first skb is sent *with* ref taken, as scm_ref is set to true for
first skb.
quoted
If second skb cannot be built, we exit this system call with an already
queued skb. Receiver can then access to freed memory.
No, we do have reference set.  For first skb, in unix_scm_to_skb.  For the
second skb (which is the last skb), in scm_sent.  Should the second skb alloc failed,
we'll release the ref in scm_destroy.  Otherwise, the receiver will release
the references will consuming the skb.
This is crap. This is not the intent of the code I read from the patch.

unless scm_ref really means scm_noref ?

I really hate this patch. I mean it.

I read it 10 times, spent 2 hours and still dont understand it.
Sorry, scm_ref means "sender hold a scm reference". I should add comment for it.
quoted hunk ↗ jump to hunk
@@ -1577,6 +1577,7 @@ static int unix_stream_sendmsg(struct kiocb *kiocb, struct socket *sock,
       int sent = 0;
       struct scm_cookie tmp_scm;
       bool fds_sent = false;
+       bool scm_ref = true;
       int max_level;

       if (NULL == siocb->scm)
@@ -1637,12 +1638,15 @@ static int unix_stream_sendmsg(struct kiocb *kiocb, struct socket *sock,
                */
               size = min_t(int, size, skb_tailroom(skb));

+               /* pass the scm reference to the very last skb */

HERE: I understand : on the last skb, set scm_ref to false.
So comment is wrong.

+               if (sent + size >= len)
+                       scm_ref = false;

-               /* Only send the fds and no ref to pid in the first buffer */
-               err = unix_scm_to_skb(siocb->scm, skb, !fds_sent, fds_sent);
+               /* Only send the fds in the first buffer */
+               err = unix_scm_to_skb(siocb->scm, skb, !fds_sent, scm_ref);
               if (err < 0) {
                       kfree_skb(skb);
-                       goto out;
+                       goto out_err;
               }



As I said, we should revert the buggy patch, and rewrite a performance
fix from scratch, with not a single get_pid()/put_pid() in fast path.

read()/write() on AF_UNIX sockets should not use a single
get_pid()/put_pid().

This is a serious regression we should fix at 100%, not 50% or even 75%,
adding serious bugs.



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