Thread (14 messages) 14 messages, 4 authors, 2025-09-25

Re: [PATCH 1/2] drivers/base/node: merge register_one_node() and register_node() to a single function.

From: Donet Tom <hidden>
Date: 2025-09-25 13:22:25
Also in: linux-mm, lkml

On 9/25/25 3:04 PM, Mike Rapoport wrote:
On Thu, Sep 25, 2025 at 10:54:07AM +0200, David Hildenbrand wrote:
quoted
On 24.09.25 20:40, Donet Tom wrote:
quoted
register_one_node() and register_node() are small functions.
This patch merges them into a single function named register_node()
to improve code readability.

No functional changes are introduced.

Signed-off-by: Donet Tom <redacted>
---
[...]
quoted
   /**
    * unregister_node - unregister a node device
    * @node: node going away
@@ -869,7 +842,13 @@ void register_memory_blocks_under_node_hotplug(int nid, unsigned long start_pfn,
   }
   #endif /* CONFIG_MEMORY_HOTPLUG */
-int register_one_node(int nid)
+/*
We can directly convert this to proper kernel doc by using /**
quoted
+ * register_node - Setup a sysfs device for a node.
+ * @nid - Node number to use when creating the device.
+ *
+ * Initialize and register the node device.
and briefly describing what the return value means

"Returns 0 on success, ..."
For kernel-doc it should be

Return: 0 on success, ...
Sure I will change it.

quoted
quoted
+ */
+int register_node(int nid)
   {
   	int error;
   	int cpu;
@@ -880,14 +859,23 @@ int register_one_node(int nid)
   		return -ENOMEM;
   	INIT_LIST_HEAD(&node->access_list);
-	node_devices[nid] = node;
-	error = register_node(node_devices[nid], nid);
+	node->dev.id = nid;
+	node->dev.bus = &node_subsys;
+	node->dev.release = node_device_release;
+	node->dev.groups = node_dev_groups;
+
+	error = device_register(&node->dev);
   	if (error) {
-		node_devices[nid] = NULL;
Wondering why we did have this temporary setting of the node_devices[] in
there. But I cannot immediately spot why it was required.
register_cpu_under_node() references node_devices, so that assignment can
be moved just before the loop that adds CPUs to node.

Sure.

Thank you

  
quoted
-- 
Cheers

David / dhildenb
  
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