Re: KASAN: use-after-free Read in task_is_descendant
From: Oleg Nesterov <oleg@redhat.com>
Date: 2018-10-26 13:04:48
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On 10/26, Tetsuo Handa wrote:
Since the "child" passed to task_is_descendant() has at least one reference
count taken by find_get_task_by_vpid(), rcu_dereference(walker->real_parent)
in the first iteration
while (child->pid > 0) {
if (!thread_group_leader(child))
walker = rcu_dereference(child->group_leader);
if (walker == parent) {
rc = 1;
break;
}
walker = rcu_dereference(walker->real_parent);
}
must not trigger use-after-free bug.Yes,
Thus, when this use-after-free was
detected at rcu_dereference(walker->real_parent), the memory pointed by
"walker" must have been released between
while (walker->pid > 0) {
if (!thread_group_leader(walker))
walker = rcu_dereference(walker->group_leader);
and
walker = rcu_dereference(walker->real_parent);
}this is possible too, rcu callback which frees the task_struct can run int between
because otherwise use-after-free would have been reported at walker->pid or thread_group_leader(walker) or rcu_dereference(walker->group_leader).
Well, I do not know how much kasan is "percise", but if it is "perfect" then you are right,
Then, what pid_alive(child) is testing?
I tried to explain this in my previous email. I even mentioned that we could do another check, say, ->sighand != NULL, or list_empty(child->sibling) with the same effect.
Suppose p1 == p2->real_parent and p2 == p3->real_parent, and p1 exited when p2 tried to attach on p1, p2->real_parent was pointing to already (or about to be) freed p1.
No, p2->real_parent will be updated. If p1 exits it will re-parent its children including p2. Again, did you read my previous email? Let me repeat, of course I can be wrong. But so far I am answering the same questions again and again... Oleg.