Re: [PATCH 1/5] KVM: Move wiping of the kvm->vcpus array to common code
From: Marc Zyngier <maz@kernel.org>
Date: 2021-11-06 11:18:26
Also in:
kvm, kvmarm, linuxppc-dev
From: Marc Zyngier <maz@kernel.org>
Date: 2021-11-06 11:18:26
Also in:
kvm, kvmarm, linuxppc-dev
On Fri, 05 Nov 2021 20:12:12 +0000, Sean Christopherson [off-list ref] wrote:
On Fri, Nov 05, 2021, Marc Zyngier wrote:quoted
All architectures have similar loops iterating over the vcpus, freeing one vcpu at a time, and eventually wiping the reference off the vcpus array. They are also inconsistently taking the kvm->lock mutex when wiping the references from the array....quoted
+void kvm_destroy_vcpus(struct kvm *kvm) +{ + unsigned int i; + struct kvm_vcpu *vcpu; + + kvm_for_each_vcpu(i, vcpu, kvm) + kvm_vcpu_destroy(vcpu); + + mutex_lock(&kvm->lock);But why is kvm->lock taken here? Unless I'm overlooking an arch, everyone calls this from kvm_arch_destroy_vm(), in which case this is the only remaining reference to @kvm. And if there's some magic path for which that's not true, I don't see how it can possibly be safe to call kvm_vcpu_destroy() without holding kvm->lock, or how this would guarantee that all vCPUs have actually been destroyed before nullifying the array.
I asked myself the same question two years ago, and couldn't really understand the requirement. However, x86 does just that, so I preserved the behaviour. If you too believe that this is just wrong, I'm happy to drop the locking altogether. If that breaks someone's flow, they'll shout soon enough. Thanks, M. -- Without deviation from the norm, progress is not possible.