[RFC PATCH 12/29] memblock: replace alloc_bootmem_low with memblock_alloc_low
From: Mike Rapoport <hidden>
Date: 2018-09-05 16:02:31
Also in:
linux-mm, linuxppc-dev, lkml, sparclinux
Subsystem:
arm64 port (aarch64 architecture), the rest · Maintainers:
Catalin Marinas, Will Deacon, Linus Torvalds
The alloc_bootmem_low(size) allocates low memory with default alignement and can be replcaed by memblock_alloc_low(size, 0) Signed-off-by: Mike Rapoport <redacted> --- arch/arm64/kernel/setup.c | 2 +- arch/unicore32/kernel/setup.c | 2 +- 2 files changed, 2 insertions(+), 2 deletions(-)
diff --git a/arch/arm64/kernel/setup.c b/arch/arm64/kernel/setup.c
index 5b4fac4..cf7a7b7 100644
--- a/arch/arm64/kernel/setup.c
+++ b/arch/arm64/kernel/setup.c@@ -213,7 +213,7 @@ static void __init request_standard_resources(void) kernel_data.end = __pa_symbol(_end - 1); for_each_memblock(memory, region) { - res = alloc_bootmem_low(sizeof(*res)); + res = memblock_alloc_low(sizeof(*res), 0); if (memblock_is_nomap(region)) { res->name = "reserved"; res->flags = IORESOURCE_MEM;
diff --git a/arch/unicore32/kernel/setup.c b/arch/unicore32/kernel/setup.c
index c2bffa5..9f163f9 100644
--- a/arch/unicore32/kernel/setup.c
+++ b/arch/unicore32/kernel/setup.c@@ -207,7 +207,7 @@ request_standard_resources(struct meminfo *mi) if (mi->bank[i].size == 0) continue; - res = alloc_bootmem_low(sizeof(*res)); + res = memblock_alloc_low(sizeof(*res), 0); res->name = "System RAM"; res->start = mi->bank[i].start; res->end = mi->bank[i].start + mi->bank[i].size - 1;
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2.7.4