Hi,
On 12/12/16 15:05, Bartosz Golaszewski wrote:
quoted hunk ↗ jump to hunk
+&lcdc {
+ status = "okay";
+ pinctrl-names = "default";
+ pinctrl-0 = <&lcd_pins>;
+
+ ports {
+ #address-cells = <1>;
+ #size-cells = <0>;
+
+ lcdc_out: port@1 {
+ #address-cells = <1>;
+ #size-cells = <0>;
+ reg = <1>;
+
+ lcdc_out_vga: endpoint {
+ reg = <0>;
+ remote-endpoint = <&vga_bridge_in>;
+ };
+ };
+ };
+};
This is not correct. LCDC has just one output, so port@1 doesn't make
sense. It's port@0. But with just one port, you can leave "ports" away.
And you don't need the port's label for anything, if I'm not mistaken. So:
&lcdc {
status = "okay";
pinctrl-names = "default";
pinctrl-0 = <&lcd_pins>;
port {
lcdc_out_vga: endpoint {
remote-endpoint = <&vga_bridge_in>;
};
};
};
Tomi