Thread (5 messages) read the whole thread 5 messages, 3 authors, 2017-08-29

Re: usage of meshctl with zephyr node

From: Laczen JMS <hidden>
Date: 2017-08-29 17:57:40

Hi Luiz,

Thanks for the reply. Zephyr does support the onoff model. Using the
silicon lab mesh program for android I can control the onoff server
model on the node.

What I don't know is if I can use the onoff command in meshctl to
control the onoff server model on the node. I am trying to provision,
configure and control a
node using meshctl. The provisioning works, I am doubting the
configuring and controlling.

For the configuring I am using: configure nodeID, add-appkey, bind, is this OK ?

For the controlling I am using onoff nodeID, onoff 1/0, is this OK?

Kind regards,

Jehudi

2017-08-29 19:38 GMT+02:00 Luiz Augusto von Dentz [off-list ref]:
Hi,

On Tue, Aug 29, 2017 at 4:50 PM, Laczen JMS [off-list ref] wrote:
quoted
Hi,

I have tried to use meshctl with a zephyr node, but I can't figure out
how to use it. I have a zephyr node that is unprovisioned and I'm
doing the following:

[meshctl] # discover-unprovisioned on -> works and gives a new
unprovisioned node (dddd000..)
[meshctl] # discover-unprovisioned off
[meshctl] # provision dddd -> works
[Zephyr Mesh-Node-0100] # configure 0100
[config: Target = 0100] # add-appkey 0 -> works: Node 0100 AppKey Status Success
[config: Target = 0100] # bind 0 0 1000 -> works: Node 0100 Model App
Status Success
Element 0100 AppIdx 000
        ModelId 1000
        Binding successful AppIdx 000
[config: Target = 0100] # back
[Zephyr Mesh-Node-0100] # onoff 0100
I don't thing Zephyr supports onoff model, that might explain why this
is failing.
quoted
[on/off: Target = 0100]# onoff 1 fails (does nothing) The debugging on
the node gives the following message:
[bt] [WRN] sdu_recv: No matching AppKey
adding some extra debugging lines in the node gives the following information:
(AID(&hdr) != keys->id):
[bt] [WRN] sdu_recv: Appkey IDs hdr:31 keys:46

Am I using meshctl incorrect ? I am doubting the bind command.

Thanks, and kind regards,

Jehudi
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Luiz Augusto von Dentz
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