Hi Maxime,

On Thu, Aug 18, 2022 at 3:42 PM Maxime Ripard [off-list ref] wrote:

On Thu, Aug 18, 2022 at 02:57:55PM +0200, Geert Uytterhoeven wrote:

quoted

On Thu, Aug 18, 2022 at 2:39 PM Maxime Ripard [off-list ref] wrote:

quoted

On Wed, Aug 17, 2022 at 04:01:48PM +0200, Geert Uytterhoeven wrote:

quoted

quoted

I've looked around and it looks like the entire blanking area is
supposed to be 40 pixels in interlaced, but I couldn't find anywhere how

625 lines - 575[*] visible lines = 50 lines.

[*] BT.656 uses 576 visible lines as that's a multiple of 2, for splitting
     a frame in two fields of equal size.

"visible" is relative, as it includes the overscan region.
Some PAL monitors used with computers had knobs to control width/height
and position of the screen, so you could make use of most or all of
the overscan region

It brings back some memories :)

quoted

but on a real TV you're limited to ca. 640x512 (on PAL) which is what
an Amiga used by default (with a 14 MHz pixclock).

quoted

quoted

it's supposed to be split between the upper and lower margins and the
sync period.

"Field Synchronization of PAL System" on
http://martin.hinner.info/vga/pal.html shows the split.

Thanks, that's excellent as well.

I'm mostly done with a function that creates a PAL mode, but I still
have one question.

If I understand well, the blanking period is made up (interlace) of 16
pulses for the first field, 14 for the second, each pulse taking half a
line. That amount to 30 pulses, so 15 lines.

I first assumed that the pre-equalizing pulses would be the back porch,
the long sync pulses the vsync, and the post-equalizing pulses the front
porch. But... we're still missing 35 lines to amount to 625 lines, that
seems to be counted in the field itself (305 lines == (575 + 35) / 2)

So I guess my assumption was wrong to begin with.

The back porch is the number of lines between the last "visible" line
and the start of the synchronization pulse, i.e. "l" in the "Field
Synchronization of PAL System" drawing.
Virtual sync length is "m".
The front porch is the number of lines between the end of
the synchronization pulse, and the first "visible" line, i.e.
"j - l - m" (I think you used "n", thus missing lines 6-23 and 319-335).

Ah, yes, that makes sense

quoted

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You seem to have used a fixed vsync in amifb to 4 lines, and I don't

Actually "m" is 2.5 lines in the first field, and 3 lines in the second field,
so "4" is not that much off of 2.5 + 3.

Is it? If I'm reading that drawing well, l before the first field starts
on the second half of line 623 and stops at the end of line 625, so 2.5
line, and on the second field starts at the beginning of line 311, and
stops half-way through 313 so 2.5 line again.

Then, for the first field, m starts at the beginning of line 1, stops
half-way through line 3, so 2.5 line indeed, and then on the second
field starts on the second half of 313 and stops at the end of line 315.
So 2.5 again?

Thus, both should be 5?

Possibly. Note that this for the official broadcast PAL.

I never looked at these signals with a scope, but I wouldn't be
surprised if some
device on't bother implementing the "half-line-sync", and synchronize
the start and stop of the vertical
sync signal with the start of a horizontal.

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understand how you come up with the upper and lower margins (or rather,
how they are linked to what's described in that page)

These margins probably came from the Amiga hardware reference manual,
for the default 640x512 (PAL) and 640x400 (NTSC) modes.

Ok.

I started adding more sanity checks to my code, and I just realised I
don't seem to be able to reach 720 pixels over a single line though. If
I understood it properly, and according to [1] the active part of a line
is supposed to be 51.95us, and the blanking period taking 12.05us. [2]
in the timing section has pretty much the same numbers, so it looks
sane.

At 13.5Mhz, a pixel is going to take roughly 74ns, and 51950 / 74 = 702
pixels

It seems we can go push it to 52350 ns, but that still gives us only 706
pixels.

Similarly, if I just choose to ignore that limit and just take the
active time I need, 720 * 74 = 53280ns

That leaves us 10720ns for the blanking period, and that's not enough to
fit even the minimum of the front porch, hsync and back porch (1.55 +
4.5 + 5.5 = 11.55us).

Are those constraints merely recommendations, or am I missing something?

You are missing that the parts near the borders of the full image are
part of the overscan range, and may or may not be visible, depending
on your actual display.
The full 768x576 image size from BT.656 is not visible on a typical PAL display,
and is more of an "absolute maximum rating", guaranteed to cover more
than analog PAL.

Gr{oetje,eeting}s,

                        Geert

--
Geert Uytterhoeven -- There's lots of Linux beyond ia32 -- geert@linux-m68k.org

In personal conversations with technical people, I call myself a hacker. But
when I'm talking to journalists I just say "programmer" or something like that.
                                -- Linus Torvalds

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