[PATCH v3 09/10] PM / Hibernate: Publish pages restored in-place to arch code
From: james.morse@arm.com (James Morse)
Date: 2015-12-07 11:28:44
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linux-pm
Hi Pavel, On 05/12/15 09:35, Pavel Machek wrote:
On Thu 2015-11-26 17:32:47, James Morse wrote:quoted
Some architectures require code written to memory as if it were data to be 'cleaned' from any data caches before the processor can fetch them as new instructions. During resume from hibernate, the snapshot code copies some pages directly, meaning these architectures do not get a chance to perform their cache maintenance. Create a new list of pages that were restored in place, so that the arch code can perform this maintenance when necessary.Umm. Could the copy function be modified to do the neccessary flushing, instead?
The copying is done by load_image_lzo() using memcpy() if you have compression enabled, and by load_image() using swap_read_page() if you don't. I didn't do it here as it would clean every page copied, which was the worrying part of the previous approach. If there is an architecture where this cache-clean operation is expensive, it would slow down restore. I was trying to benchmark the impact of this on 32bit arm when I spotted it was broken. This allocated-same-page code path doesn't happen very often, so we don't want this to have an impact on the 'normal' code path. On 32bit arm I saw ~20 of these allocations out of ~60,000 pages. This new way allocates a few extra pages during restore, and doesn't assume that flush_cache_range() needs calling. It should have no impact on architectures that aren't using the new list.
Alternatively, can you just clean the whole cache before jumping to the new kernel?
On arm64, cleaning the whole cache means cleaning all of memory by virtual address, which would be a high price to pay when we only need to clean the pages we copied. The current implementation does clean all the page it copies, the problem is the ~0.03% that are copied behind its back. This patch publishes where those pages are. Thanks! James