On Tuesday 18 October 2011, Lee Jones wrote:
On 17/10/11 17:18, Greg KH wrote:
quoted
On Mon, Oct 17, 2011 at 12:52:54PM +0100, Lee Jones wrote:
quoted
+{
+ struct soc_device *soc_dev =
+ container_of(dev, struct soc_device, dev);
+
+ sysfs_remove_group(&dev->kobj, &soc_attr_group);
+
+ if (device_is_registered(dev))
+ device_unregister(dev);
Why is this call needed?
To unregister a previously unregistered device?
Is that wrong?
See Jamie's excellent explanation: you don't need to check
for device_is_registered() here, but just call device_unregister
unconditionally.
quoted
quoted
+
+ bus_unregister(&soc_bus_type);
What happens if you have more than one SOC device? I think you just
oopsed.
I think you're right.
When to you suggest we unregister the bus?
Do it in the same way as registering it, as a module_exit() function
below the initcall that instantiates it. These interfaces usually come
in pairs, so if something does not look symmetric, you should better
have another look.
Arnd