On Mon 29-02-16 18:58:17, Oleg Nesterov wrote:
On 02/29, Michal Hocko wrote:
quoted
On Mon 29-02-16 18:38:45, Oleg Nesterov wrote:
quoted
In this case you do not need put_task_struct().
Why not? Both are after get_proc_task which takes a reference to the
task...
Yes, but we already have put_task_struct(task) in the "out_mm" path, so
"goto out_mm" should work just fine?
OK, got what you mean now. That's what I did and is on the way. I just
thought you mean that put_task_struct is implicit for other reason.
--
Michal Hocko
SUSE Labs
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