Re: [PATCH v4 1/4] Makefile: generate Perl header from template file
From: Johannes Sixt <hidden>
Date: 2017-12-01 16:59:55
Am 29.11.2017 um 16:56 schrieb Dan Jacques:
quoted hunk ↗ jump to hunk
@@ -1989,6 +1986,15 @@ GIT-PERL-DEFINES: FORCE echo "$$FLAGS" >$@; \ fi +GIT-PERL-HEADER: $(PERL_HEADER_TEMPLATE) GIT-PERL-DEFINES perl/perl.mak Makefile + $(QUIET_GEN)$(RM) $@ && \ + INSTLIBDIR=`MAKEFLAGS= $(MAKE) -C perl -s --no-print-directory instlibdir` && \ + INSTLIBDIR_EXTRA='$(PERLLIB_EXTRA_SQ)' && \ + INSTLIBDIR="$$INSTLIBDIR$${INSTLIBDIR_EXTRA:+:$$INSTLIBDIR_EXTRA}" && \ + sed -e 's=@@PATHSEP@@=$(pathsep)=g' \
This doesn't work, unfortunately. When $(pathsep) is ';', we get an incomplete sed expression because ';' is also a command separator in the sed language.
+ -e 's=@@INSTLIBDIR@@='$$INSTLIBDIR'=g' \ + $< >$@+ && \ + mv $@+ $@ .PHONY: gitweb gitweb:
-- Hannes