Re: [PATCH v8 01/12] bswap: add 64 bit endianness helper get_be64
From: Jeff King <hidden>
Date: 2017-09-24 03:51:34
On Sat, Sep 23, 2017 at 11:31:50PM +0000, Ben Peart wrote:
quoted
diff --git a/compat/bswap.h b/compat/bswap.h index 6b22c4621..9dc79bdf5100644--- a/compat/bswap.h +++ b/compat/bswap.h@@ -183,8 +183,8 @@ static inline uint32_t get_be32(const void *ptr) staticinline uint64_t get_be64(const void *ptr) { const unsigned char *p = ptr; - return (uint64_t)get_be32(p[0]) << 32 | - (uint64_t)get_be32(p[4]) << 0; + return (uint64_t)get_be32(p + 0) << 32 | + (uint64_t)get_be32(p + 4) << 0;This is surprising. Every other function in the file uses the p[x] syntax. Just for consistency, is there a way to stick to that syntax but still make it work correctly? Is there a typecast that can make it work?
The other ones are accessing the byte values directly, but since you are
building on get_be32 here, you have to pass the pointer. So:
return (uint64_t)get_be32(&p[0]) << 32 |
(uint64_t)get_be32(&p[4]) << 0;
would work. Or of course you could just spell it out like the others:
return (uint64_t)p[0] << 56 |
(uint64_t)p[1] << 48 |
(uint64_t)p[2] << 40 |
(uint64_t)p[3] << 32 |
(uint64_t)p[4] << 24 |
(uint64_t)p[5] << 16 |
(uint64_t)p[6] << 8 |
(uint64_t)p[7] << 0;
I suspect compilers would end up with the same output either way (on
x86, "gcc -O2" actually turns the whole thing into a bswap instruction).
-Peff