The regular expression currently expects a single word for the
type, but it may be something like "struct foo".
Add support for it.
Signed-off-by: Mauro Carvalho Chehab <mchehab+huawei@kernel.org>
Acked-by: Randy Dunlap <redacted>
Tested-by: Randy Dunlap <redacted>
---
tools/lib/python/kdoc/kdoc_parser.py | 4 ++--
1 file changed, 2 insertions(+), 2 deletions(-)
diff --git a/tools/lib/python/kdoc/kdoc_parser.py b/tools/lib/python/kdoc/kdoc_parser.py
index 0b6cba442d72..21cc4e19a1e8 100644
--- a/tools/lib/python/kdoc/kdoc_parser.py
+++ b/tools/lib/python/kdoc/kdoc_parser.py
@@ -1026,7 +1026,7 @@ class KernelDoc:
default_val = None
- r= KernRe(OPTIONAL_VAR_ATTR + r"[\w_]*\s+(?:\*+)?([\w_]+)\s*[\d\]\[]*\s*(=.*)?")
+ r= KernRe(OPTIONAL_VAR_ATTR + r"\s*[\w_\s]*\s+(?:\*+)?([\w_]+)\s*[\d\]\[]*\s*(=.*)?")
if r.match(proto):
if not declaration_name:
declaration_name = r.group(1)@@ -1037,7 +1037,7 @@ class KernelDoc:
r.groups(), proto)
else:
- r= KernRe(OPTIONAL_VAR_ATTR + r"(?:[\w_]*)?\s+(?:\*+)?(?:[\w_]+)\s*[\d\]\[]*\s*(=.*)?")
+ r= KernRe(OPTIONAL_VAR_ATTR + r"(?:[\w_\s]*)?\s+(?:\*+)?(?:[\w_]+)\s*[\d\]\[]*\s*(=.*)?")
if r.match(proto):
default_val = r.group(1)--
2.52.0