Re: [PATCH net-next v6 04/12] net: pse-pd: Add support for PSE power domains
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From: Kory Maincent <kory.maincent@bootlin.com>
Date: 2025-03-20 15:46:28
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On Mon, 17 Mar 2025 10:59:02 +0100 Oleksij Rempel [off-list ref] wrote:
On Tue, Mar 04, 2025 at 11:18:53AM +0100, Kory Maincent wrote:
quoted
+static int pse_register_pw_ds(struct pse_controller_dev *pcdev) +{ + int i; + + for (i = 0; i < pcdev->nr_lines; i++) { + struct regulator_dev *rdev = pcdev->pi[i].rdev; + struct pse_power_domain *pw_d; + struct regulator *supply; + bool present = false; + unsigned long index; + + /* No regulator or regulator parent supply registered. + * We need a regulator parent to register a PSE power domain + */ + if (!rdev || !rdev->supply) + continue; +Should we use xa_lock() before iteration over the map?
I am scratching my head to find out the case where it may be needed. The only case I think of is two PSE controller with PSE PI using the same power supply. Which is not a good idea for well distributing power. In this case we could have two pse_register_pw_ds running concurrently and we could have issues. Not only the iteration over the map should be protected but also the content of the pw_d entry. Also when we unbind one of the PSE controller it will remove all the PSE power domains event if they are used by another PSE. :/ I need to add refcount and lock on the PSE power domains to fix this case!
quoted
+ xa_for_each(&pse_pw_d_map, index, pw_d) { + /* Power supply already registered as a PSE power + * domain. + */ + if (regulator_is_equal(pw_d->supply, rdev->supply)) { + present = true; + pcdev->pi[i].pw_d = pw_d; + break; + } + } + if (present) + continue; + + pw_d = devm_pse_alloc_pw_d(pcdev->dev); + if (IS_ERR_OR_NULL(pw_d)) + return PTR_ERR(pw_d);It is better to break the loop and roll back previous allocations.
This will be done by pse_flush_pw_ds called by devm_pse_controller_release as the pse_controller_register failed. Regards, -- Köry Maincent, Bootlin Embedded Linux and kernel engineering https://bootlin.com