Re: [PATCH net v5 1/4] ax25: Use kernel universal linked list to implement ax25_dev_list
From: Dan Carpenter <hidden>
Date: 2024-05-07 10:11:05
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linux-hams, lkml
On Tue, May 07, 2024 at 02:59:17PM +0530, Ratheesh Kannoth wrote:
On 2024-05-07 at 12:33:39, Duoming Zhou (duoming@zju.edu.cn) wrote:quoted
The origin ax25_dev_list implements its own single linked list, which is complicated and error-prone. For example, when deleting the node of ax25_dev_list in ax25_dev_device_down(), we have to operate on the head node and other nodes separately. This patch uses kernel universal linked list to replace original ax25_dev_list, which make the operation of ax25_dev_list easier. There are two points that need to notice: [1] We should add a check to judge whether the list is empty before INIT_LIST_HEAD in ax25_dev_device_up(), otherwise it will empty the list for each new ax25_dev added. [2] We should do "dev->ax25_ptr = ax25_dev;" and "dev->ax25_ptr = NULL;" while holding the spinlock, otherwise the ax25_dev_device_up() and ax25_dev_device_down() could race, we're not guaranteed to find a match ax25_dev in ax25_dev_device_down(). Suggested-by: Dan Carpenter <redacted> Signed-off-by: Duoming Zhou <redacted> -ax25_dev *ax25_dev_list; +static struct list_head ax25_dev_list; DEFINE_SPINLOCK(ax25_dev_lock); ax25_dev *ax25_addr_ax25dev(ax25_address *addr)@@ -34,7 +35,7 @@ ax25_dev *ax25_addr_ax25dev(ax25_address *addr) ax25_dev *ax25_dev, *res = NULL; spin_lock_bh(&ax25_dev_lock); - for (ax25_dev = ax25_dev_list; ax25_dev != NULL; ax25_dev = ax25_dev->next) + list_for_each_entry(ax25_dev, &ax25_dev_list, list) if (ax25cmp(addr, (const ax25_address *)ax25_dev->dev->dev_addr) == 0) { res = ax25_dev; ax25_dev_hold(ax25_dev);@@ -52,6 +53,9 @@ void ax25_dev_device_up(struct net_device *dev) { ax25_dev *ax25_dev; + /* Initialized the list for the first entry */ + if (!ax25_dev_list.next) + INIT_LIST_HEAD(&ax25_dev_list);if you define ax25_dev_list using 'static LIST_HEAD(ax25_dev_list)', you need this conditional check and initialization ?
Ah, yes. That's the proper way to do it. regards, dan carpenter