Re: [RFC nf-next v3 1/2] netfilter: bpf: support prog update
From: Alexei Starovoitov <hidden>
Date: 2023-12-22 22:23:56
Also in:
bpf, lkml, netfilter-devel
On Thu, Dec 21, 2023 at 11:06 PM D. Wythe [off-list ref] wrote:
On 12/21/23 5:11 AM, Alexei Starovoitov wrote:quoted
On Wed, Dec 20, 2023 at 6:09 AM D. Wythe [off-list ref] wrote:quoted
From: "D. Wythe" <alibuda@linux.alibaba.com> To support the prog update, we need to ensure that the prog seen within the hook is always valid. Considering that hooks are always protected by rcu_read_lock(), which provide us the ability to access the prog under rcu. Signed-off-by: D. Wythe <alibuda@linux.alibaba.com> --- net/netfilter/nf_bpf_link.c | 63 ++++++++++++++++++++++++++++++++++----------- 1 file changed, 48 insertions(+), 15 deletions(-)diff --git a/net/netfilter/nf_bpf_link.c b/net/netfilter/nf_bpf_link.c index e502ec0..9bc91d1 100644 --- a/net/netfilter/nf_bpf_link.c +++ b/net/netfilter/nf_bpf_link.c@@ -8,17 +8,8 @@ #include <net/netfilter/nf_bpf_link.h> #include <uapi/linux/netfilter_ipv4.h> -static unsigned int nf_hook_run_bpf(void *bpf_prog, struct sk_buff *skb, - const struct nf_hook_state *s) -{ - const struct bpf_prog *prog = bpf_prog; - struct bpf_nf_ctx ctx = { - .state = s, - .skb = skb, - }; - - return bpf_prog_run(prog, &ctx); -} +/* protect link update in parallel */ +static DEFINE_MUTEX(bpf_nf_mutex); struct bpf_nf_link { struct bpf_link link;@@ -26,8 +17,20 @@ struct bpf_nf_link { struct net *net; u32 dead; const struct nf_defrag_hook *defrag_hook; + struct rcu_head head;I have to point out the same issues as before, but will ask them differently... Why do you think above rcu_head is necessary?quoted
}; +static unsigned int nf_hook_run_bpf(void *bpf_link, struct sk_buff *skb, + const struct nf_hook_state *s) +{ + const struct bpf_nf_link *nf_link = bpf_link; + struct bpf_nf_ctx ctx = { + .state = s, + .skb = skb, + }; + return bpf_prog_run(rcu_dereference_raw(nf_link->link.prog), &ctx); +} + #if IS_ENABLED(CONFIG_NF_DEFRAG_IPV4) || IS_ENABLED(CONFIG_NF_DEFRAG_IPV6) static const struct nf_defrag_hook * get_proto_defrag_hook(struct bpf_nf_link *link,@@ -126,8 +129,7 @@ static void bpf_nf_link_release(struct bpf_link *link) static void bpf_nf_link_dealloc(struct bpf_link *link) { struct bpf_nf_link *nf_link = container_of(link, struct bpf_nf_link, link); - - kfree(nf_link); + kfree_rcu(nf_link, head);Why is this needed ? Have you looked at tcx_link_lops ?Introducing rcu_head/kfree_rcu is to address the situation where the netfilter hooks might still access the link after bpf_nf_link_dealloc.
Why do you think so?
nf_hook_run_bpf
const struct
bpf_nf_link *nf_link = bpf_link;
bpf_nf_link_release
nf_unregister_net_hook(nf_link->net, &nf_link->hook_ops);
bpf_nf_link_dealloc
free(link)
bpf_prog_run(link->prog);
I had checked the tcx_link_lops ,it's seems it use the synchronize_rcu()
to solve theWhere do you see such code in tcx_link_lops ?
same problem, which is also the way we used in the first version. https://lore.kernel.org/bpf/1702467945-38866-1-git-send-email-alibuda@linux.alibaba.com/ (local) However, we have received some opposing views, believing that this is a bit overkill, so we decided to use kfree_rcu. https://lore.kernel.org/bpf/20231213222415.GA13818@breakpoint.cc/ (local)quoted
quoted
} static int bpf_nf_link_detach(struct bpf_link *link)@@ -162,7 +164,34 @@ static int bpf_nf_link_fill_link_info(const struct bpf_link *link, static int bpf_nf_link_update(struct bpf_link *link, struct bpf_prog *new_prog, struct bpf_prog *old_prog) { - return -EOPNOTSUPP; + struct bpf_nf_link *nf_link = container_of(link, struct bpf_nf_link, link); + int err = 0; + + mutex_lock(&bpf_nf_mutex);Why do you need this mutex? What race does it solve?To avoid user update a link with differ prog at the same time. I noticed that sys_bpf() doesn't seem to prevent being invoked by user at the same time. Have I missed something?
You're correct that sys_bpf() doesn't lock anything. But what are you serializing in this bpf_nf_link_update() ? What will happen if multiple bpf_nf_link_update() without mutex run on different CPUs in parallel ?