Thread (25 messages) flat view 25 messages, 5 authors, 2018-12-13

Re: [PATCH 1/3] rhashtable: further improve stability of rhashtable_walk

From: Paolo Abeni <pabeni@redhat.com>
Date: 2018-07-06 10:12:28
Also in: lkml

On Fri, 2018-07-06 at 19:55 +1000, NeilBrown wrote:
On Fri, Jul 06 2018, Paolo Abeni wrote:
quoted
Note: the code under test is a pending new patch I'm holding due to the
above issue, I can send it as RFC to share the code if you think it may
help.
I'd suggest post it.  I may not get a chance to look at it, but if you
don't post it, then I definitely won't :-)
Oks, thanks, I just spammed the list (and you ;)
quoted
quoted
@@ -867,15 +866,39 @@ void *rhashtable_walk_next(struct rhashtable_iter *iter)
 	bool rhlist = ht->rhlist;
 
 	if (p) {
-		if (!rhlist || !(list = rcu_dereference(list->next))) {
-			p = rcu_dereference(p->next);
-			list = container_of(p, struct rhlist_head, rhead);
-		}
-		if (!rht_is_a_nulls(p)) {
-			iter->skip++;
-			iter->p = p;
-			iter->list = list;
-			return rht_obj(ht, rhlist ? &list->rhead : p);
+		if (!rhlist && iter->p_is_unsafe) {
+			/*
+			 * First time next() was called after start().
+			 * Need to find location of 'p' in the list.
+			 */
+			struct rhash_head *p;
+
+			iter->skip = 0;
+			rht_for_each_rcu(p, iter->walker.tbl, iter->slot) {
+				iter->skip++;
+				if (p <= iter->p)
+					continue;
Out of sheer ignorance, I really don't understand the goal of the above
conditional ?!?
I hoped the patch description would cover that:
     With this patch:
     - a new object is always inserted after the last object with a
       smaller address, or at the start.  This preserves the property,
       important when allowing objects to be removed and re-added, that
       an object is never inserted *after* a position that it previously
       held in the list.

The items in each table slot are stored in order of the address of the
item.  So to find the first item in a slot that was not before the
previously returned item (iter->p), we step forward while this item is
<= that one. 

Does that help at all?
Yes, it's very clear. Before I dumbly skipped some slices of the patch.

Thanks,

Paolo
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