From: David Laight <hidden> Date: 2016-09-20 11:32:44
From: Jason Baron
Sent: 19 September 2016 19:34
...
sizeof(struct bnx2x_mcast_list_elem) = 24. So there are 170 per
page on x86. So if we want to fit 2,048 elements, we need 12 pages.
If you only need to save the mcast addresses you could use a 'heap'
that requires no overhead per entry and gives you O(log) lookup.
6 bytes per entry is 682 in a 4k page.
David