Re: [PATCH] ip_tunnel: fix ip_tunnel_lookup
From: Dmitry Popov <hidden>
Date: 2014-07-09 00:48:06
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On Tue, 08 Jul 2014 15:12:10 -0700 (PDT) David Miller [off-list ref] wrote:
From: Dmitry Popov <redacted> Date: Sat, 5 Jul 2014 02:26:37 +0400quoted
@@ -205,6 +207,8 @@ struct ip_tunnel *ip_tunnel_lookup(struct ip_tunnel_net *itn, hlist_for_each_entry_rcu(t, head, hash_node) { if (t->parms.i_key != key || + t->parms.iph.saddr != 0 || + t->parms.iph.daddr != 0 || !(t->dev->flags & IFF_UP)) continue;I don't really understand the logic of these tests. Usually the canonical way to test these kinds of things is: if (parms->saddr && parms->saddr != saddr) goto no_match; But you are signalling a non-match any time the address is not a wildcard. Why?
Because that's exactly what I want: to skip any non-wildcard tunnels. How I see ip_tunnel_lookup logic: 1) try to find exact match (and if found return this tunnel): tunnel.saddr == iph.daddr && tunnel.daddr == iph.saddr && key_matched() 2) try to find matched (local) wildcard tunnel: tunnel.saddr == any && tunnel.daddr == iph.saddr && key_matched() 3) try to find matched (remote) wildcard tunnel: tunnel.saddr == iph.daddr && tunnel.daddr == any && key_matched() (there is also a test for multicast tunnel, but let's skip it for simplicity) 4) try to find matched (full) wildcard tunnel: tunnel.saddr == any && tunnel.daddr == any && key_matched() 5) if nothing found return default tunnel. According to this logic, in 4th loop (the one you quoted) we have to test that tunnel.daddr == any && tunnel.saddr == any. In my opinion those two new lines are the best way to achieve it.