2012/7/2 David Miller [off-list ref]:
From: roy.qing.li@gmail.com
Date: Mon, 2 Jul 2012 11:18:59 +0800
quoted
- if (opt) {
- newnp->opt = ipv6_dup_options(newsk, opt);
- if (opt != np->opt)
- sock_kfree_s(sk, opt, opt->tot_len);
This is bogus, if we copy the options into a new copy in
ipv6_dup_options() we have to free the old one or else we
leak it.
Do you mean I should free newnp->opt firstly ?
If I understand it right, I think we do not need to free it. the
process is below:
newsk = tcp_v4_syn_recv_sock(sk, skb, req, dst);
..
newnp = inet6_sk(newsk);
..
memcpy(newnp, np, sizeof(struct ipv6_pinfo));
..
newnp->opt = NULL;
So newnp->opt is not a effective memory.
Thanks.
-Roy