Thread (10 messages) 10 messages, 3 authors, 2012-05-27

Re: [PATCH] xfrm: take iphdr size into account for esp payload size calculation

From: Steffen Klassert <steffen.klassert@secunet.com>
Date: 2012-05-11 10:39:41
Also in: lkml

On Thu, May 10, 2012 at 09:02:49PM -0400, Benjamin Poirier wrote:
The value returned by this function is tuned for tcp segment size:
1) from tcp_mtu_to_mss()
mss = pmtu - tcp_hlen - net_hlen
2) frame structure for transport mode
mtu = mss + tcp_hlen + esp_header_len(esp_payload_len) + ah_len + net_hlen
I think you can simplify the calculations here, this
calculation should not depend on any special layer 4
protocol.
The "mtu" parameter of esp4_get_mtu is in fact mtu - ah_len.
The return value of esp4_get_mtu is put into pmtu.

If we put 1 and 2 together we have:
pmtu = mtu - ah_len - esp_header_len(esp_payload_len)
with esp_payload_len = mss + tcp_hlen

This formula expands to:
pmtu = mtu - ah_len - (header_len + align(align(pmtu - net_hlen + 2, blksize),
	esp->padlen) - (pmtu - net_hlen) + alen)

and simplifies to:
pmtu = (mtu - ah_len - net_hlen - header_len - alen) & ~(max(blksize,
	esp->padlen) - 1) + (net_hlen - 2)

which, in the context of esp4_get_mtu, becomes:
((mtu - x->props.header_len - crypto_aead_authsize(esp->aead) - sizeof(struct
iphdr)) & ~(align - 1)) + (sizeof(struct iphdr) - 2)

This is the same formula as before, except for sizeof(struct iphdr) which was
missing.
Well, makes sense. I use transport mode very rarely, so I never noticed this.
But I was sure that it worked correct in tunnel mode. 

Thanks.
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