Thread (7 messages) 7 messages, 4 authors, 2012-04-10

Re: a F-RTO question

From: Li Yu <hidden>
Date: 2012-03-28 06:43:18

于 2012年03月28日 13:35, Yuchung Cheng 写道:
On Tue, Mar 27, 2012 at 9:08 PM, Li Yu[off-list ref]  wrote:
quoted
于 2012年03月28日 11:49, Chao Pei 写道:
quoted
quoted
Hi,

        I have a question about tcp_process_frto(), the below source
code :

static int tcp_process_frto(struct sock *sk, int flag)
{
        .....

        if (!before(tp->snd_una, tp->frto_highmark)) {
                tcp_enter_frto_loss(sk, ...);
                return 1;
        }

        .....

}

        As my understanding, the tp->frto_highmark likes tp->high_seq,
it saves the seqno SND_NXT when a TCP connection enters F-RTO phase,
is it the variable "recovery" in NewReno? So I think that if snd_una is
equal with or after frto_highmark, which means peer ack new data, so
why we enter Loss state here?

        Thanks!

Yu
If snd_una advances to frto_highmark, it is likely that the hole was
filled by the retransimitted packet, which means the original packet
was likely to have been lost.
So, we should enter loss state.
I do not agree with it, if snd_una advanced to frto_highmark, which means
peer acks whole window of data instead of just one segment, and
we can not make sure that reason of peer sends ack is whether it received
original segment or retransmitted segment.

Even, the reason is latter, it also means the netowrk already is
recovered from temporarily congestion or disordered state, so we also should
not enter loss state.
Like you said there is some ambiguity and F-RTO takes the conservative approach.
You can find answers to your question in RFC 5682  (Section 2.2). Unless the RTO
is proven to be spurious, TCP should reduce window and performs
slow-start regardlessly.
I think I got it, if the new ack covers "frto_highmark",
it may mean the fast retransmitted segments are lost likely.

In RFC5682:

   If the first acknowledgment after the RTO retransmission covers the
   "recover" point at algorithm step (2a), there is not enough evidence
   that a non-retransmitted segment has arrived at the receiver after
   the timeout.  This is a common case when a fast retransmission is
   lost and has been retransmitted again after an RTO, while the rest of
   the unacknowledged segments were successfully delivered to the TCP
   receiver before the retransmission timeout.  Therefore, the timeout
   cannot be declared spurious in this case.

And as Chao's words, if the RTO is proven, we should enter
slow-start then.

Thanks!

Yu
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