From: Roy.Li <redacted>
When calling snmp6_alloc_dev fails, the snmp6 relevant memory
are freed by snmp6_alloc_dev. Calling in6_dev_finish_destroy
will free these memory twice.
Double free will lead that undefined behavior occurs.
Signed-off-by: Roy.Li <redacted>
Acked-by: Eric Dumazet <redacted>