Hi,

Am 19.06.2011 um 17:22 schrieb Dominik Kaspar:

Hello again,

I have another question to Linux TCP and packet reordering. What
exactly happens, when a packet is so much delayed (but not causing a
timeout), that it gets overtaken by a retransmitted version of itself?
It seems to me that this results in "SACK reneging", but I don't
really understand why...

in theory, you can detect this case with a combination of DSACK
and timestamps. However, in practice a reordering delay greater than
RTT will likely case an RTO (see RFC4653). IMO, if you have an packet
reordering with an delay greater that the RTT, you have much more problems  
that SACK reneging

The simplified situation goes this:
- Segment A gets sent and very much delayed (but not causing RTO)
- Segments B, C, D cause dupACKs
- Segment A_ret is retransmitted and ACKed (sent over new path)
- Some more segments E, F, ... are sent and ACKed
- Segment A (the delayed one) arrives at the receiver.
- Now what exactly happens next...?

Receiver sends a DSACK

I use default Linux TCP (with sack=1, dsack=1, fack=1, timestamps=1,
...) and the above described series of events is cause why
transparently forwarding IP packets over multiple paths with RTTs of
10 and 100 milliseconds.

I'd appreciate your help - best regards,
Dominik

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// Dipl.-Inform. Alexander Zimmermann
// Department of Computer Science, Informatik 4
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