Re: NIU driver unmap_page call
From: Andy Fleming <hidden>
Date: 2009-06-01 20:58:38
On Jun 1, 2009, at 5:11 AM, David Miller wrote:
From: Andy Fleming <redacted> Date: Fri, 29 May 2009 17:38:50 -0500quoted
I'm trying to figure out what this code does: if ((page->index + rp->rbr_block_size) - rcr_size == addr) { *link = (struct page *) page->mapping; np->ops->unmap_page(np->device, page->index, PAGE_SIZE, DMA_FROM_DEVICE); page->index = 0; page->mapping = NULL; rp->rbr_refill_pending++; } else get_page(page); It's clear it's taking the opportunity to remove the page from the hash table, and to unmap the page, but I'm not familiar enough with this nic to understand what the if statement is looking for. My first thought was that it was looking to see if this was the first buffer in the page?It's looking to see if this is the LAST chunk in the page, not the first.
Hmm... I'm still misunderstanding something. rbr_blocks_per_page implies that each page has multiple blocks. This looks like it is checking to see if the current buffer is the last buffer in the block. There is similar code in the niu_rx_pkt_ignore function, which uses PAGE_SIZE in place of rbr_block_size.
rcr_size is the size of the sub-buffers within the page that the chip is carving out of the page. Since when we allocated the page initially this obtained on reference to the page, we increment for every chunk given out to an SKB except the last one.
But in niu_rbr_add_page(), the function does:
atomic_add(rp->rbr_blocks_per_page - 1,
&compound_head(page)->_count);
Which I thought was already doing the necessary accounting.
Andy