Re: [PATCH] tcp: splice as many packets as possible at once
From: Willy Tarreau <w@1wt.eu>
Date: 2009-01-09 18:55:33
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Hi Eric, On Fri, Jan 09, 2009 at 04:42:44PM +0100, Eric Dumazet wrote: (...)
Willy patch makes splice() behaving like tcp_recvmsg(), but we might call tcp_cleanup_rbuf() several times, with copied=1460 (for each frame processed) I wonder if the right fix should be done in tcp_read_sock() : this is the one who should eat several skbs IMHO, if we want optimal ACK generation. We break out of its loop at line 1246 if (!desc->count) /* this test is always true */ break; (__tcp_splice_read() set count to 0, right before calling tcp_read_sock()) So code at line 1246 (tcp_read_sock()) seems wrong, or pessimistic at least.
That's a very interesting discovery that you made here. I have made
mesurements with this line commented out just to get an idea. The
hardest part was to find a CPU-bound machine. Finally I slowed my
laptop down to 300 MHz (in fact, 600 with throttle 50%, but let's
call that 300). That way, I cannot saturate the PCI-based tg3 and
I can observe the effects of various changes on the data rate.
- original tcp_splice_read(), with "!timeo" : 24.1 MB/s
- modified tcp_splice_read(), without "!timeo" : 32.5 MB/s (+34%)
- original with line #1246 commented out : 34.5 MB/s (+43%)
So you're right, avoiding calling tcp_read_sock() all the time
gives a nice performance boost.
Also, I found that tcp_splice_read() behaves like this when breaking
out of the loop :
lock_sock();
while () {
...
__tcp_splice_read();
...
release_sock();
lock_sock();
if (break condition)
break;
}
release_sock();
Which means that when breaking out of the loop on (!timeo)
with ret > 0, we do release_sock/lock_sock/release_sock.
So I tried a minor modification, consisting in moving the
test before release_sock(), and leaving !timeo there with
line #1246 commented out. That's a noticeable winner, as
the data rate went up to 35.7 MB/s (+48%).
Also, in your second mail, you're saying that your change
might return more data than requested by the user. I can't
find why, could you please explain to me, as I'm still quite
ignorant in this area ?
Thanks,
Willy