From: Evgeniy Polyakov <redacted>
Date: Fri, 7 Nov 2008 20:28:10 +0300

On Thu, Nov 06, 2008 at 11:53:35AM -0800, Lovich, Vitali (vlovich@qualcomm.com) wrote:

quoted

Are there any consequences to bypassing qdisc (other than not participating in any load balancing)?  Also, since any users using the tx ring approach would have to write new code, it would be part of the documentation that the send behaviour is optimized for the least latency and highest throughput, thus no guarantees and assumptions can be made about the path the data takes through the stack.

qdisc is a base for multiqueue NICs (and all others too now), you can not bypass it there.

Right.