Re: [TCP] IPV6 : Change a divide into a right shift in tcp_v6_send_ack()

YOSHIFUJI Hideaki / 吉藤英明 a écrit :

In article [ref] (at Fri, 21 Dec 2007 07:03:58 +0100), Eric Dumazet [off-list ref] says:

quoted

Because tot_len is signed in tcp_v6_send_ack(), tot_len/4 forces compiler
to emit an integer divide, while we can help it to use a right shift,
less expensive.

Are you really sure?
At least, gcc-4.1.2-20061115 (debian) does not make any difference.

And, IMHO, because shift for signed variable is fragile, so we should
avoid using it.

Yes I am sure, but maybe you are on x86_64 ?

gcc-4.2.2 on x86

# objdump --disassemble net/ipv6/tcp_ipv6.o|grep -6 idiv
       b2:       66 8b 42 02             mov    0x2(%edx),%ax
       b6:       ba 04 00 00 00          mov    $0x4,%edx
       bb:       89 d7                   mov    %edx,%edi
       bd:       66 89 45 00             mov    %ax,0x0(%ebp)
       c1:       89 d8                   mov    %ebx,%eax
       c3:       99                      cltd
       c4:       f7 ff                   idiv   %edi
       c6:       88 c2                   mov    %al,%dl
       c8:       8a 45 0c                mov    0xc(%ebp),%al
       cb:       c1 e2 04                shl    $0x4,%edx
       ce:       83 e0 0f                and    $0xf,%eax
       d1:       09 d0                   or     %edx,%eax
       d3:       88 45 0c                mov    %al,0xc(%ebp)


If you think tot_len can be negative, I understand you can be against this 
patch. But I am sure it's allways > 0, even if I am a total ipv6 newbie :)

Thank you