Re: [PATCH v4 1/7] mm/zone_device: Add order argument to folio_free callback
From: Zi Yan <ziy@nvidia.com>
Date: 2026-01-12 18:55:31
Also in:
amd-gfx, dri-devel, intel-xe, kvm, linux-cxl, linux-mm, linux-pci, lkml, nouveau
On 12 Jan 2026, at 13:25, Jason Gunthorpe wrote:
On Mon, Jan 12, 2026 at 12:46:57PM -0500, Zi Yan wrote:quoted
On 12 Jan 2026, at 11:50, Jason Gunthorpe wrote:quoted
On Mon, Jan 12, 2026 at 11:31:04AM -0500, Zi Yan wrote:quoted
quoted
folio_free() 1) Allocator finds free memory 2) zone_device_page_init() allocates the memory and makes refcount=1 3) __folio_put() knows the recount 0. 4) free_zone_device_folio() calls folio_free(), but it doesn't actually need to undo prep_compound_page() because *NOTHING* can use the page pointer at this point. 5) Driver puts the memory back into the allocator and now #1 can happen. It knows how much memory to put back because folio->order is valid from #2 6) #1 happens again, then #2 happens again and the folio is in the right state for use. The successor #2 fully undoes the work of the predecessor #2.But how can a successor #2 undo the work if the second #1 only allocates half of the original folio? For example, an order-9 at PFN 0 is allocated and freed, then an order-8 at PFN 0 is allocated and another order-8 at PFN 256 is allocated. How can two #2s undo the same order-9 without corrupting each other’s data?What do you mean? The fundamental rule is you can't read the folio or the order outside folio_free once it's refcount reaches 0.There is no such a rule. In core MM, folio_split(), which splits a high order folio to low order ones, freezes the folio (turning refcount to 0) and manipulates the folio order and all tail pages compound_head to restructure the folio.That's different, I am talking about reaching 0 because it has been freed, meaning there are no external pointers to it. Further, when a page is frozen page_ref_freeze() takes in the number of references the caller has ownership over and it doesn't succeed if there are stray references elsewhere. This is very important because the entire operating model of split only works if it has exclusive locks over all the valid pointers into that page. Spurious refcount failures concurrent with split cannot be allowed. I don't see how pointing at __folio_freeze_and_split_unmapped() can justify this series.
But from anyone looking at the folio state, refcount == 0, compound_head is set, they cannot tell the difference. If what you said is true, why is free_pages_prepare() needed? No one should touch these free pages. Why bother resetting these states.
quoted
Your fundamental rule breaks this. Allowing compound information to stay after a folio is freed means you cannot tell whether a folio is under split or freed.You can't refcount a folio out of nothing. It has to come from a memory location that already is holding a refcount, and then you can incr it.
Right. There is also no guarantee that all code is correct and follows this. My point here is that calling prep_compound_page() on a compound page does not follow core MM’s conventions. Best Regards, Yan, Zi