Thread (37 messages) 37 messages, 10 authors, 2022-06-30

RE: [PATCH v2 3/3] arch/*/: remove CONFIG_VIRT_TO_BUS

From: David Laight <hidden>
Date: 2022-06-30 10:33:07
Also in: linux-alpha, linux-arch, linux-iommu, linux-m68k, linux-scsi, lkml

From: Christophe Leroy
Sent: 30 June 2022 10:40

Le 30/06/2022 à 10:04, David Laight a écrit :
quoted
From: Michael Schmitz
quoted
Sent: 29 June 2022 00:09

Hi Arnd,

On 29/06/22 09:50, Arnd Bergmann wrote:
quoted
On Tue, Jun 28, 2022 at 11:03 PM Michael Schmitz [off-list ref] wrote:
quoted
On 28/06/22 19:03, Geert Uytterhoeven wrote:
quoted
quoted
The driver allocates bounce buffers using kmalloc if it hits an
unaligned data buffer - can such buffers still even happen these days?
No idea.
Hmmm - I think I'll stick a WARN_ONCE() in there so we know whether this
code path is still being used.
kmalloc() guarantees alignment to the next power-of-two size or
KMALLOC_MIN_ALIGN, whichever is bigger. On m68k this means it
is cacheline aligned.
And all SCSI buffers are allocated using kmalloc? No way at all for user
space to pass unaligned data?
I didn't think kmalloc() gave any such guarantee about alignment.
I does since commit 59bb47985c1d ("mm, sl[aou]b: guarantee natural
alignment for kmalloc(power-of-two)")
Looks like it is done for 'power-of-two' less than PAGE_SIZE.
This may not help scsi tape writes which could easily be (say) 47 bytes.
I think that only guarantees 2 byte alignment on m68k.
(Although increasing the min-alignment on m68k to 4 (or even 8)
will probably make no measurable difference.)

What happens above PAGE_SIZE?
Any structure with a trailing [] field could easily request
'64k + a_bit' bytes.
You don't really want to extend this to 128k - but I suspect
that is what happens.

	David
 
Christophe
quoted
There are cache-line alignment requirements on systems with non-coherent
dma, but otherwise the alignment can be much smaller.

One of the allocators adds a header to each item, IIRC that can
lead to 'unexpected' alignments - especially on m68k.

dma_alloc_coherent() does align to next 'power of 2'.
And sometimes you need (eg) 16k allocates that are 16k aligned.

	David

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Registered Address Lakeside, Bramley Road, Mount Farm, Milton Keynes, MK1 1PT, UK
Registration No: 1397386 (Wales)
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