From: Segher Boessenkool
Sent: 06 October 2021 22:27
On Thu, Oct 07, 2021 at 05:44:00AM +0900, Stafford Horne wrote:
quoted
You have defined of_get_cpu_hwid to return u64, will this create compiler
warnings when since we are storing a u64 into a u32?
It seems only if we make with W=3.
Yes. This is done by -Wconversion, "Warn for implicit conversions that
may alter a value."
quoted
I thought we usually warned on this.
The microsoft compiler does - best to turn all those warnings off.
This warning is not in -Wall or -Wextra either, it suffers too much from
false positives. It is very natural to just ignore the high bits of
modulo types (which is what "unsigned" types *are*). Or the bits that
"fall off" on a conversion. The C standard makes this required
behaviour, it is useful, and it is the only convenient way of getting
this!
I've also seen a compiler convert:
struct->char_member = (char)(int_val & 0xff);
into:
reg = int_val;
reg &= 0xff; // for the & 0xff
reg &= 0xff; // for the cast
struct->char_member = low_8bits(reg);
You really don't want the extra noise.
I'll bet that (char)int_val is actually an arithmetic expression.
So its type will be 'int'.
David
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