Re: [RFC v6 01/62] powerpc: Free up four 64K PTE bits in 4K backed HPTE pages

On Thu, Jul 20, 2017 at 11:21:51AM +0530, Aneesh Kumar K.V wrote:

.....

quoted

 	/*

@@ -116,8 +104,8 @@ int __hash_page_4K(unsigned long ea, unsigned long access, unsigned long vsid,
 		 * On hash insert failure we use old pte value and we don't
 		 * want slot information there if we have a insert failure.
 		 */
-		old_pte &= ~(H_PAGE_HASHPTE | H_PAGE_F_GIX | H_PAGE_F_SECOND);
-		new_pte &= ~(H_PAGE_HASHPTE | H_PAGE_F_GIX | H_PAGE_F_SECOND);
+		old_pte &= ~(H_PAGE_HASHPTE);
+		new_pte &= ~(H_PAGE_HASHPTE);
 		goto htab_insert_hpte;
 	}

With the current path order and above hunk we will breaks the bisect I guess. With the above, when
we convert a 64k hpte to 4khpte, since this is the first patch, we
should clear that H_PAGE_F_GIX and H_PAGE_F_SECOND. We still use them
for 64k. I guess you should move this hunk to second patch.

true. it should move to the next patch. Will fix it.
RP