Thread (36 messages) 36 messages, 9 authors, 2016-07-15

Re: [PATCH v2 0/4] implement vcpu preempted check

From: Wanpeng Li <hidden>
Date: 2016-07-07 10:12:55
Also in: kvm, linux-s390, lkml, virtualization

2016-07-07 17:42 GMT+08:00 Peter Zijlstra [off-list ref]:
On Thu, Jul 07, 2016 at 04:48:05PM +0800, Wanpeng Li wrote:
quoted
2016-07-06 20:28 GMT+08:00 Paolo Bonzini [off-list ref]:
quoted
Hmm, you're right.  We can use bit 0 of struct kvm_steal_time's flags to
indicate that pad[0] is a "VCPU preempted" field; if pad[0] is 1, the
VCPU has been scheduled out since the last time the guest reset the bit.
 The guest can use an xchg to test-and-clear it.  The bit can be
accessed at any time, independent of the version field.
If one vCPU is preempted, and guest check it several times before this
vCPU is scheded in, then the first time we can get "vCPU is
preempted", however, since the field is cleared, the second time we
will get "vCPU is running".

Do you mean we should call record_steal_time() in both kvm_sched_in()
and kvm_sched_out() to record this field? Btw, if we should keep both
vcpu->preempted and kvm_steal_time's "vCPU preempted" field present
simultaneous?
I suspect you want something like so; except this has holes in.

We clear KVM_ST_PAD_PREEMPT before disabling preemption and we set it
after enabling it, this means that if we get preempted in between, the
vcpu is reported as running even though it very much is not.
Paolo also point out this to me offline yesterday: "Please change
pad[12] to "__u32 preempted; __u32 pad[11];" too, and remember to
update Documentation/virtual/kvm/msr.txt!". Btw, do this in preemption
notifier means that the vCPU is real preempted on host, however,
depends on vmexit is different semantic I think.

Regards,
Wanpeng Li
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