Re: [PATCH v2] cpuidle: Fix last_residency division
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From: Shreyas B Prabhu <hidden>
Date: 2016-06-24 16:01:55
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On 06/24/2016 03:41 PM, Arnd Bergmann wrote:
On Friday, June 24, 2016 9:00:48 AM CEST David Laight wrote:quoted
The intent of the >> 10 was probably to avoid an expensive 64bit divide. So maybe something like: diff = time_end - time_start; if (diff >= INT_MAX/2) diff_32 = INT_MAX/2/1000; else diff_32 = diff; diff_32 += diff_32 >> 6; diff_32 >>= 10; } Adding an extra 1/32 makes the division by be something slightly below 1000.Why not change the definition of the time to nanoseconds and update the users accordingly? I see that cpuidle_enter_state() writes to the last_residency value, and it is read in three places: ladder_select_state(), menu_update() and show_state_time() (for sysfs).
Updating show_state_time() to convert ns to us gets bit messy since show_state_##_name which is used for disable, usage and time simply returns state_usage->_name. And state_usage->time updation happens in cpuidle_enter_state() itself.
If those functions are called less often than cpuidle_enter_state(), we could just move the division there. Since the divisor is constant, do_div() can convert it into a multiply and shift, or we could use your the code you suggest above, or use a 32-bit division most of the time: if (diff <= UINT_MAX) diff_32 = (u32)diff / NSECS_PER_USEC; else diff_32 = div_u64(diff, NSECS_PER_USEC; which gcc itself will turn into a multiplication or series of shifts on CPUs on which that is faster.
I'm not sure which division method of the three suggested here to use. Does anyone have a strong preference? --Shreyas