Thread (11 messages) 11 messages, 5 authors, 2016-06-29

Re: [PATCH v2] cpuidle: Fix last_residency division

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From: Shreyas B Prabhu <hidden>
Date: 2016-06-24 16:01:55
Also in: linux-pm


On 06/24/2016 03:41 PM, Arnd Bergmann wrote:
On Friday, June 24, 2016 9:00:48 AM CEST David Laight wrote:
quoted
The intent of the >> 10 was probably to avoid an expensive 64bit divide.
So maybe something like:
        diff = time_end - time_start;
        if (diff >= INT_MAX/2)
                diff_32 = INT_MAX/2/1000;
        else
                diff_32 = diff;
                diff_32 += diff_32 >> 6;
                diff_32 >>= 10;
        }

Adding an extra 1/32 makes the division by be something slightly below 1000.
Why not change the definition of the time to nanoseconds and update
the users accordingly?

I see that cpuidle_enter_state() writes to the last_residency value,
and it is read in three places: ladder_select_state(), menu_update()
and show_state_time() (for sysfs).
Updating show_state_time() to convert ns to us gets bit messy since
show_state_##_name which is used for disable, usage and time simply
returns state_usage->_name. And state_usage->time updation happens in
cpuidle_enter_state() itself.
If those functions are called less often than cpuidle_enter_state(),
we could just move the division there. Since the divisor is constant,
do_div() can convert it into a multiply and shift, or we could use
your the code you suggest above, or use a 32-bit division most of
the time:

	if (diff <= UINT_MAX)
		diff_32 = (u32)diff / NSECS_PER_USEC;
	else
		diff_32 = div_u64(diff, NSECS_PER_USEC;

which gcc itself will turn into a multiplication or series of
shifts on CPUs on which that is faster.
I'm not sure which division method of the three suggested here to use.
Does anyone have a strong preference?

--Shreyas
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