Re: [PATCH 2/6] 8xx: Update TLB asm so it behaves as linux mm expects.
From: Joakim Tjernlund <hidden>
Date: 2009-10-09 06:20:55
Benjamin Herrenschmidt [off-list ref] wrote on 09/10/2009 02:53:31:
Subject: Re: [PATCH 2/6] 8xx: Update TLB asm so it behaves as linux mm expects. On Fri, 2009-10-09 at 00:44 +0200, Joakim Tjernlund wrote:quoted
accessed == 1 and present = 0 is impossible, right? So basically just copy over accessed to present and linux mm set both when trapping to C.No, when present = 0, then the rest of the PTE can contain unrelated things, you can't trust ACCESSED.
Ah, OK.
quoted
What about the execute perms in Level 2 descriptor, page 247?Not useful, not fine grained enough.quoted
quoted
You still need to massage the PP bits into place. I don't see that happening.Not at the moment, later.quoted
As it is, your PTE contains for bit 20 and 21, which translates to: PTE: Translates to PP bits: RW: 0 USER: 0 00 supervisor RW (ok) RW: 0 USER: 1 01 supervisor RW user RO (WRONG) RW: 1 USER: 0 10 supervisor RW user RW (WRONG) RW: 1 USER: 1 11 supervisor RO user RO (WRONG)You got USER and RW swapped and the table is different for exec.Hrm, let me see... yes. You are right, I mixed RW and USER. However, I don't think the PP bits change do they ? IE. Basically, Read == Exec at the page level. So the table isn't really different between I and D. However, indeed, since you don't have a unified TLB, the case can be made that we can ignore R vs. W in the iTLB case. In which case, you get for iTLB: PTE: Translates to PP bits: RW: 0 USER: 0 00 supervisor X only (ok) RW: 0 USER: 1 10 supervisor X user X (ok) RW: 1 USER: 0 01 supervisor X user X (WRONG) RW: 1 USER: 1 11 supervisor X user X (ok) So a page with _PAGE_RW and not _PAGE_USER would still be executable from user... oops :-)
Yes, it is not perfect, but should work for now.
I think what you want for iTLB is just basically have a base of 00
and or-in _PAGE_USER only (ie, keep _PAGE_RW clear with a rlwinm)
so that you basically get supervisor X only if _PAGE_USER is 0 and
both X if _PAGE_USER is 1
For the dTLB, the table becomes (including your inversion of _PAGE_RW)
PTE: Translates to PP bits:
RW: 0 USER: 0 01 supervisor RW user RO (WRONG)
RW: 0 USER: 1 11 supervisor RO user RO (ok)
RW: 1 USER: 0 00 supervisor RW only (ok)
RW: 1 USER: 1 10 supervisor RW user RW (ok)
So it's -almost- right :-) You still got the RW:0 USER:0 case wrong,
ie a read-only kernel page would be user readable.Which will be fixed once I activate: #if 0 /* Not yet */ /* Honour kernel RO, User NA */ andi. r11, r10, _PAGE_USER | _PAGE_RW bne- cr0, 5f ori r10,r10, 0x200 /* Extended encoding, bit 22 */ #endif
You can work around that by never setting kernel pages read-only (which we do mostly), but in the grand scheme of things, my trick I proposed initially would sort it out all including support for kernel RO :-)
Not convinced that your trick will be a win. The other bits will need to move around too. Maybe I misunderstand something?