Thread (4 messages) 4 messages, 4 authors, 2024-06-03

Re: [PATCH 1/6] fs/exec: Drop task_lock() inside __get_task_comm()

From: Eric W. Biederman <hidden>
Date: 2024-06-02 17:53:04
Also in: bpf, linux-fsdevel, linux-mm, linux-security-module, selinux

Alexei Starovoitov [off-list ref] writes:
On Sat, Jun 1, 2024 at 11:57 PM Yafang Shao [off-list ref] wrote:
quoted
On Sun, Jun 2, 2024 at 11:52 AM Eric W. Biederman [off-list ref] wrote:
quoted
Yafang Shao [off-list ref] writes:
quoted
Quoted from Linus [0]:

  Since user space can randomly change their names anyway, using locking
  was always wrong for readers (for writers it probably does make sense
  to have some lock - although practically speaking nobody cares there
  either, but at least for a writer some kind of race could have
  long-term mixed results
Ugh.
Ick.

This code is buggy.

I won't argue that Linus is wrong, about removing the
task_lock.

Unfortunately strscpy_pad does not work properly with the
task_lock removed, and buf_size larger that TASK_COMM_LEN.
There is a race that will allow reading past the end
of tsk->comm, if we read while tsk->common is being
updated.
It appears so. Thanks for pointing it out. Additionally, other code,
such as the BPF helper bpf_get_current_comm(), also uses strscpy_pad()
directly without the task_lock. It seems we should change that as
well.
Hmm. What race do you see?
If lock is removed from __get_task_comm() it probably can be removed from
__set_task_comm() as well.
And both are calling strscpy_pad to write and read comm.
So I don't see how it would read past sizeof(comm),
because 'buf' passed into __set_task_comm is NUL-terminated.
So the concurrent read will find it.
The read may race with a write that is changing the location
of '\0'.  Especially if the new value is shorter than
the old value.

If you are performing lockless reads and depending upon a '\0'
terminator without limiting yourself to the size of the buffer
there needs to be a big fat comment as to how in the world
you are guaranteed that a '\0' inside the buffer will always
be found.

Eric
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