Thread (5 messages) 5 messages, 3 authors, 2007-08-16

Re: [PATCH] dm: Fix deadlock under high i/o load in raid1 setup.

From: Heiko Carstens <hidden>
Date: 2007-08-16 00:00:03
Also in: dm-devel

On Wed, Aug 15, 2007 at 03:56:04PM -0700, Andrew Morton wrote:
On Mon, 13 Aug 2007 13:33:40 +0200
Heiko Carstens [off-list ref] wrote:
quoted
the patch below went into 2.6.18. Now my question is: why doesn't it check
if kmalloc(..., GFP_NOIO) returns with a NULL pointer?
Did I miss anything that guarentees that this will always succeed or is it
just a bug?
--- a/drivers/md/dm-raid1.c
+++ b/drivers/md/dm-raid1.c
@@ -255,7 +255,9 @@ static struct region *__rh_alloc(struct region_hash *rh, region_t region)
 	struct region *reg, *nreg;
 
 	read_unlock(&rh->hash_lock);
-	nreg = mempool_alloc(rh->region_pool, GFP_NOIO);
+	nreg = mempool_alloc(rh->region_pool, GFP_ATOMIC);
+	if (unlikely(!nreg))
+		nreg = kmalloc(sizeof(struct region), GFP_NOIO);
 	nreg->state = rh->log->type->in_sync(rh->log, region, 1) ?
 		RH_CLEAN : RH_NOSYNC;
 	nreg->rh = rh;
Yeah, that's a bug.

kmalloc(small_amount, GFP_NOIO) can fail if the calling process gets
oom-killed, and it can fail if the system is using fault-injection.

One could say "don't use fault injection" and, perhaps, "this is only
ever called by a kernel thread and kernel threads don't get oom-killed". 
But the former is lame and the latter assumes current implementation
details which could change (and indeed have in the past).
Thanks for clarifying!
So yes, I'd say this is a bug in DM.

Also, __rh_alloc() is called under read_lock(), via __rh_find().  If
__rh_alloc()'s mempool_alloc() fails, it will perform a sleeping allocation
under read_lock(), which is deadlockable and will generate might_sleep()
warnings
The read_lock() is unlocked at the beginning of the function. Unless
you're talking of a different lock, but I couldn't find any.

So at least _currently_ this should work unless somebody uses fault
injection. Would it make sense then to add the __GFP_NOFAIL flag to
the kmalloc call?

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