I noticed an error in and example on the man page for strncpy(). The page is http://www.kernel.org/doc/man-pages/online/pages/man3/strncpy.3.html
The error is in the section, "NOTES", specifically in the code example after the text:
If there is no terminating null byte in the first n characters of src,
strncpy() produces an unterminated string in dest. Programmers often prevent
this mistake by forcing termination as follows:
strncpy(buf, str, n);
if (n > 0)
buf[n - 1]= '\0';
Substituting 1 for n and "123" for str, this would equate to:
strncpy(buf, "123", 1); // buf is now "1"
if (1 > 0)
buf[1 - 1]= '\0'; // buf is now ""
Bob Eggers--
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I believe that's the correct result for a NULL-terminated string of length 1.
- bog
On 06/21/2010 01:30 PM, Bob Eggers wrote:
I noticed an error in and example on the man page for strncpy(). The page is http://www.kernel.org/doc/man-pages/online/pages/man3/strncpy.3.html
The error is in the section, "NOTES", specifically in the code example after the text:
If there is no terminating null byte in the first n characters of src,
strncpy() produces an unterminated string in dest. Programmers often prevent
this mistake by forcing termination as follows:
strncpy(buf, str, n);
if (n > 0)
buf[n - 1]= '\0';
Substituting 1 for n and "123" for str, this would equate to:
strncpy(buf, "123", 1); // buf is now "1"
if (1 > 0)
buf[1 - 1]= '\0'; // buf is now ""
Bob Eggers--
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Bill O. Gallmeister
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