RE: [PATCH RFCv3 2/3] lib/vsprintf.c: make %pD print full path for file
From: Justin He <hidden>
Date: 2021-06-15 07:18:22
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-----Original Message----- From: Rasmus Villemoes <linux@rasmusvillemoes.dk> Sent: Tuesday, June 15, 2021 3:15 PM To: Justin He <redacted>; Petr Mladek <pmladek@suse.com> Cc: Steven Rostedt <rostedt@goodmis.org>; Sergey Senozhatsky [off-list ref]; Andy Shevchenko [off-list ref]; Rasmus Villemoes [off-list ref]; Jonathan Corbet [off-list ref]; Alexander Viro [off-list ref]; Linus Torvalds <torvalds@linux- foundation.org>; Peter Zijlstra (Intel) [off-list ref]; Eric Biggers [off-list ref]; Ahmed S. Darwish [off-list ref]; linux-doc@vger.kernel.org; linux-kernel@vger.kernel.org; linux- fsdevel@vger.kernel.org Subject: Re: [PATCH RFCv3 2/3] lib/vsprintf.c: make %pD print full path for file On 15/06/2021 08.48, Justin He wrote:quoted
Hi Petrquoted
quoted
quoted
+ /* no filling space at all */ + if (buf >= end || !buf) + return buf + reserved_size; + + /* small space for long name */ + if (buf < end && prepend_len < 0) + return string_truncate(buf, end, p, dpath_len, spec);We need this only because we allowed to write the path behind spec.field_width. Do I get it right?Both of field_width and precision: "%.14pD" or "%8.14pD"Precision is never gonna be used with %p (or any of its kernel extensions) because gcc would tell you foo.c:5:13: warning: precision used with �%p� gnu_printf format [- Wformat=] 5 | printf("%.5p\n", foo); and there's no way -Wformat is going to be turned off to allow that usage. IOW, there's no need to add complexity to make "%.3pD" of something that would normally print "/foo/bar" merely print "/fo", similar to what a precision with %s would mean.
Aha, this answer my question in last email. Thank you -- Cheers, Justin (Jia He)
As for field width, I don't know if it's worth honouring, but IIRC the original %pd and %pD did that (that's where we have widen_string etc. from). Other %p extensions put the field with to some other use (e.g. the bitmap and hex string printing), so they obviously cannot simultaneously use it in the traditional sense. Rasmus
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