On 2019/7/8 22:14, Thomas Gleixner wrote:

Zhiqiang,

quoted

If HZ satisfies the condition: HZ <= MSEC_PER_SEC && !(MSEC_PER_SEC %
HZ), the return value of _msecs_to_jiffies func with m=0 is different
with different HZ setting.

quoted

------------------------------------
| HZ |	MSEC_PER_SEC / HZ | return |
------------------------------------
|1000|		1	  |   0	   |
|500 |		2	  |   1	   |
|200 |		5	  |   1	   |
|100 |		10	  |   1	   |
------------------------------------

Why only the return value of HZ=1000 is equal to 0 with m=0 ?

I don't know how you tested that, but obviously all four HZ values use
this variant:

quoted

    #if HZ <= MSEC_PER_SEC && !(MSEC_PER_SEC % HZ)
    static inline unsigned long _msecs_to_jiffies(const unsigned int m)
    {
            return (m + (MSEC_PER_SEC / HZ) - 1) / (MSEC_PER_SEC / HZ);
    }

and for all four HZ values the result is 0. Why?

For m = 0 the calculation reduces to:

      ((MSEC_PER_SEC / HZ) - 1) / (MSEC_PER_SEC / HZ)

i.e.

	(x - 1) / x	where x = [1, 2, 5, 10]

which is guaranteed to be 0 for integer math. If not, you have a compiler
problem.

Thanks,

	tglx

Thanks for your reply. Actually, I have made a low-level mistake.
I am really sorry for that.
Thanks again.