On 23.11.2021 11:09, Rafał Miłecki wrote:

[    0.000000] __clk_core_init: clk clock-controller already initialized
[    0.000000] ------------[ cut here ]------------
[    0.000000] WARNING: CPU: 0 PID: 0 at drivers/clk/bcm/clk-iproc-pll.c:802 iproc_pll_clk_setup+0x4c8/0x4f4
[    0.000000] Modules linked in:
[    0.000000] CPU: 0 PID: 0 Comm: swapper/0 Not tainted 5.10.80 #0
[    0.000000] Hardware name: BCM5301X
[    0.000000] [<c0108410>] (unwind_backtrace) from [<c0104bc4>] (show_stack+0x10/0x14)
[    0.000000] [<c0104bc4>] (show_stack) from [<c03dca28>] (dump_stack+0x94/0xa8)
[    0.000000] [<c03dca28>] (dump_stack) from [<c0118440>] (__warn+0xb8/0x114)
[    0.000000] [<c0118440>] (__warn) from [<c0118504>] (warn_slowpath_fmt+0x68/0x78)
[    0.000000] [<c0118504>] (warn_slowpath_fmt) from [<c043281c>] (iproc_pll_clk_setup+0x4c8/0x4f4)
[    0.000000] [<c043281c>] (iproc_pll_clk_setup) from [<c0818c04>] (nsp_genpll_clk_init+0x30/0x38)
[    0.000000] [<c0818c04>] (nsp_genpll_clk_init) from [<c0818634>] (of_clk_init+0x118/0x1f8)
[    0.000000] [<c0818634>] (of_clk_init) from [<c08039b0>] (time_init+0x24/0x30)
[    0.000000] [<c08039b0>] (time_init) from [<c0800d14>] (start_kernel+0x398/0x50c)
[    0.000000] [<c0800d14>] (start_kernel) from [<00000000>] (0x0)
[    0.000000] ---[ end trace fe236bfe9559ee50 ]---

It seems that Linux's clock name is derived from DT node. With multiple
clock-controller@ nodes there is a name conflict as seen above.

 From DT perspective I don't think there is anything wrong in having
multiple nodes using the same name prefix.

Could clk subsystem be somehow improved to be more /creative/ at picking
clock names? ;) Would someone be kind to take a look at this, please?

Ah, I've just realized it's not clk subsystem but actually a clk driver
that picks up a name based on DT node name.

iproc_pll_clk_setup() does:
init.name = node->name;

I should have double check that before sending my e-mail.

I can't see any helper picking a clock unique name based on DT node.
Any advise how to proceed with that?