Re: [PATCH 4/6] regulator: Initial commit of sy7636a
From: Mark Brown <broonie@kernel.org>
Date: 2021-01-18 12:37:46
Also in:
lkml
On Sat, Jan 16, 2021 at 08:25:37PM -0800, Alistair Francis wrote:
quoted hunk ↗ jump to hunk
--- /dev/null +++ b/drivers/regulator/sy7636a-regulator.c@@ -0,0 +1,233 @@ +// SPDX-License-Identifier: GPL-2.0+ +/* + * Functions to access SY3686A power management chip voltages + *
Please make the entire comment a C++ one so things look more intentional.
+ * Copyright (C) 2019 reMarkable AS - http://www.remarkable.com/ + * + * Author: Lars Ivar Miljeteig [off-list ref]
This probably needs an update.
+ * This program is free software; you can redistribute it and/or + * modify it under the terms of the GNU General Public License as + * published by the Free Software Foundation version 2. + * + * This program is distributed "as is" WITHOUT ANY WARRANTY of any + * kind, whether express or implied; without even the implied warranty + * of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the + * GNU General Public License for more details.
This boilerplate is redundant and should be removed.
+static int get_vcom_voltage_op(struct regulator_dev *rdev)
+{
+ int ret = get_vcom_voltage_mv(rdev->regmap);
+Why is this get_vcom_voltage_mv() function not in the regulator driver, and why is it not just inline here? It also needs namespacing.
+static int disable_regulator(struct regulator_dev *rdev)
+{
+ struct sy7636a *sy7636a = dev_get_drvdata(rdev->dev.parent);
+ int ret = 0;
+
+ mutex_lock(&sy7636a->reglock);
+ ret = regulator_disable_regmap(rdev);
+ usleep_range(30000, 35000);
+ mutex_unlock(&sy7636a->reglock);Why do you need this delay here, and what purpose is this lock intended to serve? I can't understand what it's intended to protect.
+ mutex_lock(&sy7636a->reglock); + ret = regulator_is_enabled_regmap(rdev); + mutex_unlock(&sy7636a->reglock);
This lock usage in particular looks confused.
+ ret = regulator_enable_regmap(rdev); + if (ret) + goto finish;
+ if (!pwr_good) {
+ dev_err(&rdev->dev, "Power good signal timeout after %u ms\n",
+ jiffies_to_msecs(t1 - t0));
+ ret = -ETIME;
+ goto finish;
+ }This doesn't undo the underlying enable, leaving the regulator in a partially enabled state.
+static const struct regulator_ops sy7636a_vcom_volt_ops = {
+ .get_voltage = get_vcom_voltage_op,
+ .enable = enable_regulator_pgood,
+ .disable = disable_regulator,
+ .is_enabled = sy7636a_regulator_is_enabled,
+};The namespacing for functions is very random and prone to clashes. Given the power good signal I'd also expect a get_status() operation.
+static int sy7636a_regulator_suspend(struct device *dev)
+{
+ int ret;
+ struct sy7636a *sy7636a = dev_get_drvdata(dev->parent);
+
+ ret = get_vcom_voltage_mv(sy7636a->regmap);
+
+ if (ret > 0)
+ sy7636a->vcom = (unsigned int)ret;
+
+ return 0;
+}What's going on here, and if you are going to store this value over suspend why not store it in a variable of the correct type? In general it's surprising to need a suspend operation for a regulator.
+ sy7636a->pgood_gpio = gdp; + dev_info(sy7636a->dev, + "Power good GPIO registered (gpio# %d)\n", + desc_to_gpio(sy7636a->pgood_gpio));
This print is just adding noise to the boot process.
Attachments
- signature.asc [application/pgp-signature] 488 bytes